4-3m^2=-266

Solution for 4-3m^2=-266 equation:

4-3m^2=-266

We move all terms to the left:

4-3m^2-(-266)=0

We add all the numbers together, and all the variables

-3m^2+270=0

a = -3; b = 0; c = +270;
Δ = b2-4ac
Δ = 02-4·(-3)·270
Δ = 3240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3240}=\sqrt{324*10}=\sqrt{324}*\sqrt{10}=18\sqrt{10}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{10}}{2*-3}=\frac{0-18\sqrt{10}}{-6}
=-\frac{18\sqrt{10}}{-6}
=-\frac{3\sqrt{10}}{-1}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{10}}{2*-3}=\frac{0+18\sqrt{10}}{-6}
=\frac{18\sqrt{10}}{-6}
=\frac{3\sqrt{10}}{-1}
$